If a motor rated at 25 horsepower is delivering 20 horsepower, what percentage of its capacity is it operating at?

Study for the 3rd Class Stationary Steam Engineer License Test. Practice with flashcards and multiple choice questions, each question has hints and explanations. Get ready for your exam!

To determine the percentage of capacity at which the motor is operating, you can use the formula:

[ \text{Percentage of capacity} = \left( \frac{\text{Output horsepower}}{\text{Rated horsepower}} \right) \times 100

]

In this case, the output horsepower is 20 and the rated horsepower is 25. Plugging these values into the formula gives:

[ \text{Percentage of capacity} = \left( \frac{20}{25} \right) \times 100 = 0.8 \times 100 = 80% ]

This calculation shows that the motor is performing at 80% of its rated capacity when it delivers 20 horsepower out of a potential 25 horsepower. This is a typical way to analyze how efficiently a piece of equipment is running in relation to its capacity, providing insight into its operational performance.

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